MODUL 2. PERCOBAAN GERBANG LOGIKA DASAR

PENYELESAIAN :

1. ) A. RANGKAIAN LOGIKA DAN SIMULASI DENGAN MULTIMEDIA LOGIC

      B. TABEL KEBENARAN DAN KESIMPULAN DARI SIMULASI MULTIMEDIA LOGIC
              

a.)   S = B(A+C) + A.C + D

      Tabel Kebenaran :

A	B	C	D	A+C	B(A+C)	A.C	B(A+C) + A.C	S = B(A+C) + A.C + D
1	1	1	1	1	1	1	1	1
1	1	1	0	1	1	1	1	1
1	1	0	1	1	1	0	1	1
1	1	0	0	1	1	0	1	1
1	0	1	1	1	0	1	1	1
1	0	1	0	1	0	1	1	1
1	0	0	1	1	0	0	0	1
1	0	0	0	1	0	0	0	0
0	1	1	1	1	1	0	1	1
0	1	1	0	1	1	0	1	1
0	1	0	1	0	0	0	0	1
0	1	0	0	0	0	0	0	0
0	0	1	1	1	0	0	0	1
0	0	1	0	1	0	0	0	0
0	0	0	1	0	0	0	0	1
0	0	0	0	0	0	0	0	0

 

Kesimpulan dari Simulasi Multimedia Logic :

SWITCH				KONDISI LED
A	B	C	D
ON	ON	ON	ON	NYALA
ON	ON	ON	OFF	NYALA
ON	ON	OFF	ON	NYALA
ON	ON	OFF	OFF	NYALA
ON	OFF	ON	ON	NYALA
ON	OFF	ON	OFF	NYALA
ON	OFF	OFF	ON	NYALA
ON	OFF	OFF	OFF	MATI
OFF	ON	ON	ON	NYALA
OFF	ON	ON	OFF	NYALA
OFF	ON	OFF	ON	NYALA
OFF	ON	OFF	OFF	MATI
OFF	OFF	ON	ON	NYALA
OFF	OFF	ON	OFF	MATI
OFF	OFF	OFF	ON	NYALA
OFF	OFF	OFF	OFF	MATI

  

b.) X = ⌐(⌐(⌐A+B)).(B.C))+ ⌐B.C

   Tabel Kebenaran :

A	B	C	⌐A	⌐B	⌐A+B	⌐(⌐A+B)	B.C	(⌐(⌐A+B)).(B.C)	⌐(⌐(⌐A+B)).(B.C))	⌐B.C	X = ⌐(⌐(⌐A+B)).(B.C))+ ⌐B.C
1	1	1	0	0	1	0	1	0	1	0	1
1	1	0	0	0	1	0	0	0	1	0	1
1	0	1	0	1	0	1	0	0	1	1	1
1	0	0	0	1	0	1	0	0	1	0	1
0	1	1	1	0	1	0	1	0	1	0	1
0	1	0	1	0	1	0	0	0	1	0	1
0	0	1	1	1	1	0	0	0	1	1	1
0	0	0	1	1	1	0	0	0	1	0	1

  

Kesimpulan dari Simulasi Multimedia Logic :

SWITCH			KONDISI LED
A	B	C
ON	ON	ON	NYALA
ON	ON	OFF	NYALA
ON	OFF	ON	NYALA
ON	OFF	OFF	NYALA
OFF	ON	ON	NYALA
OFF	ON	OFF	NYALA
OFF	OFF	ON	NYALA
OFF	OFF	OFF	NYALA

2.) a. Simulasi dengan Multimedia Logic

        

 

        

 

 

b. Tabel Kebenaran Dan Kesimpulan Dari Simulasi Multimedia Logic

Rangkaian I. ((A+⌐B).(B+C).B)

A	B	C	⌐B	(A+⌐B)	(B+C)	(A+⌐B).(B+C)	(A+⌐B).(B+C).B
1	1	1	0	1	1	1	1
1	1	0	0	1	1	1	1
1	0	1	1	1	1	1	0
1	0	0	1	1	0	0	0
0	1	1	0	0	1	0	0
0	1	0	0	0	1	0	0
0	0	1	1	1	1	0	0
0	0	0	1	1	0	0	0

  

SWITCH			KONDISI LED
A	B	C
ON	ON	ON	NYALA
ON	ON	OFF	NYALA
ON	OFF	ON	MATI
ON	OFF	OFF	MATI
OFF	ON	ON	MATI
OFF	ON	OFF	MATI
OFF	OFF	ON	MATI
OFF	OFF	OFF	MATI

  
Rangkaian II.     ⌐(⌐(S.T).(T+S))

S	T	S.T	⌐(S.T)	T+S	⌐(S.T).(T+S)	⌐(⌐(S.T).(T+S))
1	1	1	0	1	0	1
1	0	0	1	1	1	0
0	1	0	1	1	1	0
0	0	0	1	0	0	1

 

SWITCH		LED
S	T
ON	ON	NYALA
ON	OFF	MATI
OFF	ON	MATI
OFF	OFF	NYALA

Rangkaian III. (U.V)+(⌐V.W)

 

U	V	W	U.V	⌐V	⌐V.W	(U.V)+(⌐V.W)
1	1	1	1	0	0	1
1	1	0	1	0	0	1
1	0	1	0	1	1	1
1	0	0	0	1	0	0
0	1	1	0	0	0	0
0	1	0	0	0	0	0
0	0	1	0	1	1	1
0	0	0	0	1	0	0

 

SWITCH			KONDISI LED
U	V	W
ON	ON	ON	NYALA
ON	ON	OFF	NYALA
ON	OFF	ON	NYALA
ON	OFF	OFF	MATI
OFF	ON	ON	MATI
OFF	ON	OFF	MATI
OFF	OFF	ON	NYALA
OFF	OFF	OFF	MATI

  

Rangkaian IV.   (P.Q)+ ⌐(Q+P)

P	Q	P.Q	Q+P	⌐(Q+P)	(P.Q)+⌐(Q+P)
1	1	1	1	0	1
1	0	0	1	0	0
0	1	0	1	0	0
0	0	0	0	1	1

 

SWITCH		LED
P	Q
ON	ON	NYALA
ON	OFF	MATI
OFF	ON	MATI
OFF	OFF	NYALA

c. Kesimpulan
    Dari hasil output percobaan di atas dapat disimpulkan bahwa yang mempunyai fungsi sama adalah Rangkaian II dan Rangkaian IV.